1.

In m_(1)g of a metal A displaces m_(2)G of another metal B from its salt solution and if their equivalent masses are E_(1) and E_(2) respectively, then the equivalent mass of A can be expressed as:

Answer»

`E_(1)=(m_(2)xxE_(2))/(m_(1))`
`E_(1)=(m_(1))/(m_(2))xxE_(2)`
`E_(1)=(m_(1)xxm_(2))/(E_(2))`
`E_(1)=sqrt((m_(1))/(m_(2))xxE_(2))`

Answer :B


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