In Millikan oil drop experiment, a charged drop of mass `1.8 xx 10^(-14) kg` is stationary between its plates. The distance between its plates is `0.90 cm` and potential difference is `2.0` kilo volts. The number of electrons on the drop isA. `500`B. `50`C. `5`D. `0`

In Millikan oil drop experiment, a charged drop of mass `1.8 xx 10^(-1

1.	In Millikan oil drop experiment, a charged drop of mass `1.8 xx 10^(-14) kg` is stationary between its plates. The distance between its plates is `0.90 cm` and potential difference is `2.0` kilo volts. The number of electrons on the drop isA. `500`B. `50`C. `5`D. `0`
Answer» Correct Answer - C `QE = mg rArr Q = (mg)/(E) rArr n = (mgd)/(Ve)` `rArr n = (1.8 xx 10^(-14) xx 10 xx 0.9 xx 10^(-2))/(2 xx 10^(3) xx 1.6 xx 10^(-19)) = 5`

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In Millikan oil drop experiment, a charged drop of mass `1.8 xx 10^(-14) kg` is stationary between its plates. The distance between its plates is `0.90 cm` and potential difference is `2.0` kilo volts. The number of electrons on the drop isA. `500`B. `50`C. `5`D. `0`

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