1.

In NH_(4)NO_(2), the oxidation number of nitrogen will be

Answer»

`+3`
`+5`
`-3` and +3
`+3` and +5

Solution :`{:(NH_(4)NO_(2),hArr,overset(**)(N)H_(4)^(+),+,overset(**)(N)O_(2)^(-)),("(OXIDATION number)",,x+4=+1,,x-4=-1),(,,x=1-4=-3,,x=+3):}`


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