1.

In nitroprusside ion, iron and NO exist as Fe (II) and NO^(+) rather than Fe (III) and NO. These forms can be differentiated by

Answer»

estimating the concentration of iron
measuring the concentration of `CN^(-)`
measuring the solid STATE magnetic MOMENT
thermally DECOMPOSING the compound

Solution :In nitroprusside ion, Fe (II) has `d^(6)` configuration, i.e., 4 unpaired electrons which pair up for `d^(2)sp^(3)`-hybridisation and `NO^(+)` has also no unpaired electron. Hence, its magnetic moment is zero, i.e., it is diamagnetic. On the other HAND, Fe (III) has `d^(5)` configuration and NO has unpaired electron. Even after pairing up, unpaired electrons are present and it would have net magnetic moment.


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