In nitroprusside ion, the iron and `NO` exist as `Fe(II)` and `NO^(+)` rather than `Fe^(III)` and `NO`. These forms can be differentiated byA. Estmating the concentration of ironB. Measuring the concentration of ironC. Measuring the solid state magentic momentD. Thermally decomposing decomposing the compound

In nitroprusside ion, the iron and `NO` exist as `Fe(II)` and `NO^(+)`

1.	In nitroprusside ion, the iron and `NO` exist as `Fe(II)` and `NO^(+)` rather than `Fe^(III)` and `NO`. These forms can be differentiated byA. Estmating the concentration of ironB. Measuring the concentration of ironC. Measuring the solid state magentic momentD. Thermally decomposing decomposing the compound
Answer» Correct Answer - C Fe(III) has five unpaired electrons (`d^(5)` configuartion ) whereas Fe(II) has four unpaired electrons (`d^(6)` configuration). These forms can be differentiated by measuring the solid state magnetic moment.

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