The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV

The decreasing order of the boiling points of the following hydrides (

1.	The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV
Answer» Correct Answer - A The b.pt of `SbH_(3)` is higher than that of `NH_(3)`. The reason being that the stronger van der walls forces of attraction more than compensate the rease in b.pt of `NH_(3)` due to H-bonding (A ) is correct.

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The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV

The decreasing order of the boiling points of the following hydrides (i) `NH_3` (ii) `PH_3` (iii) `AsH_3` (iv) `SbH_3` (v) `H_2O` isA. VgtIVgtIgtIIIgtIIB. VgtIgtIIgtIIIgtIVC. IgtIVgtIIIgtIIgtVD. IVgtIIIgtIgtIIgtV

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