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In one A.C. generator, brushes connected with slip rings become positive and negative alternatively at the regular interval of 10 ms. Then angular frequency of this A.C. voltage would be ………. |
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Answer» 50  We can SEE that polarity of A.C. voltage changesat every half cycle i.e. at the end of every `T/2` time interval, which is given 10 MS in the STATEMENT. Hence, `T/2`=10 ms `therefore` T=20 ms = `20xx10^(-3)` s `therefore (2pi)/omega=20xx10^(-3) (because omega=(2pi)/T)` `therefore omega=(2pi)/(20xx10^(-3))` `therefore omega=100pi "rad"/s` |
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