1.

In one atom of As is added per 10^(3) atoms of Ge then the number of free electron in one mole of Ge will be ……..

Answer»

`10^(17)`
`10^(20)`
`10^(10)`
`10^(13)`

SOLUTION :`10^(10)`
1 As atom per `10^(13)` Ge atom then,
at `10^(23)` atoms of Ge?
`N=(1xx10^(23))/(10^(13))=10^(10)`


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