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In one litre of 3M solution of NaOH, H_(2)SO_(4) is added until 27.4 Kcal energy us released. Then 2 moles of CH_(3)COOH is added to the resulting solution and the final volume becomes 2 litre. If x moles of AgCN can be dissolved in the final solution, what is x xx 10^(4)? H^(+)+OH^(-)rarrH_(2)O ""DeltaH=-13.7Kcal//mol K_(sp)AgCN=10^(-12)K_(a)(CH_(3)COOH)=10^(-5) K_(a)(HCN)=10^(-9) |
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Answer» `AgCNhArr Aunderset(s)(G^(+))+Cunderset(s)(N)^(-)` `CN^(-)+UNDERSET(10^(-5))H^(+)rarrHunderset(s)CN` `(S^(2))/(10^(-5)xx10^(-12))=10^(9)` `s=10^(-4)m/L` |
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