1.

In order that a body of 15 kg weighs zero at the equator, then the angular speed of earth is : (g=10ms^(-1))

Answer»

`(1)/(80) " rad s"^(-1)`
`(1)/(400)" rad s"^(-1)`
`(1)/(800)" rad s"^(-1)`
`(1)/(1600)" rad s"^(-1)`

Solution :`mg.=0 rArr mg - mRomega^(2)=0`
`rArr omega= SQRT((g)/(R ))=sqrt((1.0)/(6.4xx10^(6)))=(1)/(800)" rad SEC"^(-1)`
Thus correct CHOICE is (c ).


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