InterviewSolution
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InterviewSolution
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In order that the resultant path on superimposing two mutually perpendicular SHM be a circle, the conditions are thatA. the amplitudes on both SHM should be equal and they should have a phase difference of `(pi)/(2)`B. the amplitude should be in the ratio 1:2 and the phase difference should be zeroC. the amplitude should be in the ratio 1:2 and the phase difference should be `(pi)/(2)`D. the amplitudes should be equal and the phase difference should be zero |
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Answer» Correct Answer - A (a) Suppose `x=A "sin" omegat` and `y= A"cos"omegat` Then by squaring and adding these two equations , we get ` x^(2)+y^(2)=A^(2)` |
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