1.

In order to increase the volume of a gas by 10%, the pressure of the gas should be:

Answer»

decreased by 10%
decreased by 1%
increased by 10%
increased by 1%

Solution :According to Boyle.s law, `PV=` constant
or `p_(1) V_(1) = p_(2) V_(2)`
If `V_(2) = V_(1) + ( V_(1) xx 10)/( 100) = 1.1 V_(1)`
`p_(2) = ( p_(1)V_(1))/( V_(2)) = ( p _(1) xx V_(1))/( 1.1V_(1)) = 0.9 p_(1) `
% DECREASE in PRESSURE
`= ( ( p_(1) - 0.9 p_(1))/( p_(1)))xx 100 = 10%`


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