1.

In PO_(4)^(3-) the formal charge on the each oxygen atom and the P-O bond order respectively are

Answer»

`-0.75, 0.6`
`-0.75, 1.0`
`-0.75, 1.25`
`-3.1,1.25`

Solution :Formal charge on an atom=
total no. of valence electrons in FREE atom - total no.of non - BONDING ELECTONS `-1/2` total no of bonding electrons
Formal charge on oxygen `=6-[6+1/2xx2]=-1`
There are total 3 oxygen atom, therefore charge=-3
Formal charge on each O-atom
`=("total charge")/("number of atoms")=(-3)/4=-0.75` and
P-O bond order
`=("total no. of bonds")/("total no of resonating structures")=5/4=1.25`


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