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In ∆POR, Q=90°,QS Is perpendicular to PR,QS=12,SR=8 Find PS |
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Answer» -step EXPLANATION:Given:PS ⊥ RQQT ⊥ PRRQ = 6, PS = 6 and PR = 12With BASE PR and height QT, A(△PQR)=12×PR×QTWith base QR and height PS, A(△PQR)=12×QR×PS∴A(△PQR)A(△PQR)=12×PR×QT12×QR×PS⇒1=PR×QTQR×PS⇒PR×QT=QR×PS⇒QT=QR×PSPR=6×612=3Hence, the measure of side QT is 3 units. |
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