In previous problem, if the body is suspended from the two springs connected in parallel, the time period will beA. `sqrt(T_1T_2)`B. `(T_1T_2)/(sqrt(T_1^2+T_2^2))`C. `sqrt((T_1^2T_2^2)/(2))`D. `(2T_1T_2)/(sqrt(T_1^2+T_2^2))`

In previous problem, if the body is suspended from the two springs con

1.	In previous problem, if the body is suspended from the two springs connected in parallel, the time period will beA. `sqrt(T_1T_2)`B. `(T_1T_2)/(sqrt(T_1^2+T_2^2))`C. `sqrt((T_1^2T_2^2)/(2))`D. `(2T_1T_2)/(sqrt(T_1^2+T_2^2))`
Answer» Correct Answer - B `k_(eq)=k_1+k_2` `(1)/(T^2)=(1)/(T_1^2)+(1)/(T_2^2)=(T_2^2+T_1^2)/(T_1^2T_2^2)` `T=sqrt((T_1^2T_2^2)/(T_1^2+T_2^2))=(T_1T_2)/(sqrt(T_1^2T_2^2)`

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In previous problem, if the body is suspended from the two springs connected in parallel, the time period will beA. `sqrt(T_1T_2)`B. `(T_1T_2)/(sqrt(T_1^2+T_2^2))`C. `sqrt((T_1^2T_2^2)/(2))`D. `(2T_1T_2)/(sqrt(T_1^2+T_2^2))`

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