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In pure crystal of silicon at 300 K temperature having number of atom n_(i)=10^(16)m^(-3). If 10^(21) atoms of phosphorus added per m^(3) then number of holes created will be …… /m^(3). |
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Answer» `10^(21)` `n_(i)^(2)=n_(E )n_(N)` `therefore n_(n)=(n_(i)^(2))/(n_(e ))=((10^(16))^(2))/(10^(21))=10^(11)m^(-3)` |
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