1.

In pure crystal of silicon at 300 K temperature having number of atom n_(i)=10^(16)m^(-3). If 10^(21) atoms of phosphorus added per m^(3) then number of holes created will be …… /m^(3).

Answer»

`10^(21)`
`10^(19)`
`10^(11)`
`10^(5)`

Solution :`10^(11)`
`n_(i)^(2)=n_(E )n_(N)`
`therefore n_(n)=(n_(i)^(2))/(n_(e ))=((10^(16))^(2))/(10^(21))=10^(11)m^(-3)`


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