1.

In Q. 103, the radiation force on the roof will be :

Answer»

`8.53 xx 10^(-5) W`
`2.3 xx 10^(-3) W`
`1.33 xx 10^(-3) W`
`5.33 xx 10^(-4) W`

Solution :`"FORCE of RADIATION"=("POWER")/(c)`
`=(1.6 xx 10^(5))/(3 xx 10^(8))=5.32 xx 10^(-4)N`


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