In qualitative analysis, the metals of Group I can be separated from other ion by precipitating them as chloride salts. A solution initially contains Ag^(+) and Pb^(2+) at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl^(-) concentration is 0.10 M. What will the concentrations of Ag^(+) and Pb^(2+) be at equilibrium (K_(sp) for AgCl = 1.8 xx 10^(-10), K_(sp) fr PbCl_(2) = 1.7 xx 10^(-5))

In qualitative analysis, the metals of Group I can be separated from o

1.	In qualitative analysis, the metals of Group I can be separated from other ion by precipitating them as chloride salts. A solution initially contains Ag^(+) and Pb^(2+) at a concentration of 0.10 M. Aqueous HCl is added to this solution until the Cl^(-) concentration is 0.10 M. What will the concentrations of Ag^(+) and Pb^(2+) be at equilibrium (K_(sp) for AgCl = 1.8 xx 10^(-10), K_(sp) fr PbCl_(2) = 1.7 xx 10^(-5))
Answer» `[AG^(+)] = 1.8 xx 10^(-9) M, [Pb^(2+)] = 1.7 xx 10^(-3)M` `[Ag^(+)] = 1.8 xx 10^(-11) M, [Pb^(2+)] = 1.7 xx 10^(-4)M` `[Ag^(+)] = 1.8 xx 10^(-7) M, [Pb^(2+)] = 1.7 xx 10^(-6)M` `[Ag^(+)] = 1.8 xx 10^(-11) M, [Pb^(2+)] = 1.7 xx 10^(-5)M` Answer :A