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In question number 45, what will be the electric field at centre O, if the charge from one of the corners (say A) is removed?

Answer»

`q/(4piepsilon_(0)R^(2))` ALONG OA
`(2q)/(4piepsilon_(0)r^(2))` along OB
`(q^(2))/(4piepsilon_(0)r^(2))` along OC
`(2q)/(4piepsilon_(0)r^(2))` along OA

Solution :When a charge q from corner A is REMOVED, electric field at O is `E_(1)=q/(4piepsilon_(0)r^(2)` along OA


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