1.

In question number 45, what will be the electric field at O if the charge q at A is replaced by -q?

Answer»

`(Q)/(4piepsilon_(0)r^(2))` ALONG OB
`(2q)/(4piepsilon_(0)r^(2))` along OA
`(4q)/(4piepsilon_(0)r^(2))` along OC
zero

Solution :If the charge q at A is replaced by -q, it is equivalent to adding charge -2q at A. Therefore, electric field at O, `E_(2)=(2q)/(4piepsilon_(0)r^(2)` along OA.


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