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In question number 7, the temperature of other interfaces (in `.^(@)C`) isA. `26.5, 0.5`B. `27.5, 1`C. `28.5, 2`D. `29.5, 3`

Answer» Correct Answer - A
`T_(1) = 27-(Ht_(1))/(K_(1)A_(1)) = 27-0.52 = 26.48^(@)C = 26.5^(@)C`
and `T_(2) = 0+ (Ht_(1))/(K_(1)A_(1)) = 0.52^(@)C`


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