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In question number 70, what is frequency of photon ?

Answer»

`3.1xx10^(15)Hz`
`3.1xx10^(18)Hz`
`9.1xx10^(15)Hz`
`9.1xx10^(18)Hz`

Solution :SINCE, `UPSILON =(C)/(lambda)`
Here, `c=3xx10^(8)MS^(-1)`,`lambda=9.7xx10^(-8)m`.
`thereforeupsilon=(3xx10^(8))/(9.7xx10^(-8))=3.1xx10^(15)Hz`.


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