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In question number 91, maximum value of magnetisation of the given domain is (Dipole moment of an iron atom `9.27 xx 10^(-24)A m^(2))`A. `8.0xx10^(5)Am^(-1)`B. `6.0xx10^(4)Am^(-1)`C. `8.0xx10^(3)Am^(-1)`D. `6.0xx10^(3)Am^(-1)` |
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Answer» Correct Answer - A Net dipole moment, `M_(N)=Nxxm` `=6.9xx10^(11)xx9.27xx10^(-24)=6.4xx10^(-12)Am^(2)` `"Net magnetisation"=(6.4xx10^(-12))/(8xx10^(-18))=8xx10^(5)Am^(-1)` |
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