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In right triangle ABC, Angle CAB =90 AF Perpendicular to CB and BD is median AC=2 CM AB= 2sqrt3 find AE |
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Answer» GIVEN : In right triangle ABC, Angle CAB =90 AE Perpendicular to CB and BD is MEDIAN AC=2 Cm AB= 2√3 To find : AE Solution: Area of Δ ABC = (1/2) * AC * AB = (1/2) * 2 * 2√3 = 2√3 cm² Area of Δ ABC = (1/2) BC * AE BC² = AC² + AB² => BC² = 2² + (2√3)² => BC² = 4 + 12 => BC² = 16 => BC = 4 Area of Δ ABC = (1/2) * 4 * AE = 2AE 2AE = 2√3 => AE = √3 AE = √3 cm Learn More: The hypotenus of a right triangle is 3 root 5.If the SMALLER SIDE is ... Find the area of a right-angled triangle of hypotenuse 91 cm and ... |
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