In Rutherford's experiment, the number of alpha- particles scattered through an angle of 60^@ by a silverfoil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of a particles scattered through an angle of 60^@ per minute is:

In Rutherford's experiment, the number of alpha- particles scattered t

1.	In Rutherford's experiment, the number of alpha- particles scattered through an angle of 60^@ by a silverfoil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of a particles scattered through an angle of 60^@ per minute is:
Answer» `(200 XX Z_(Cu))/(Z_(AG))` `200 xx ((Z_(cu))/(Z_(Ag)))^2` `200 xx (Z_(Ag ))/( Z_(Cu))` `200 xx((Z_(Ag))/( Z_(Cu)))` Solution :`200 xx ((Z_(cu))/(Z_(Ag)))^2`

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In Rutherford's experiment, the number of alpha- particles scattered through an angle of 60^@ by a silverfoil is 200 per minute. When the silver foil is replaced by a copper foil of the same thickness, the number of a particles scattered through an angle of 60^@ per minute is:

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