In Rutherford scattering experiment, if a proton is taken instead of an alpha particle, then for same distance of closest approach, how much K.E. in comparison to K.E. of a particle will be required?

In Rutherford scattering experiment, if a proton is taken instead of a

1.	In Rutherford scattering experiment, if a proton is taken instead of an alpha particle, then for same distance of closest approach, how much K.E. in comparison to K.E. of a particle will be required?
Answer» At the distance of closest approach `(r_0)`. `KE_(alpha)=((Ze^2)(2e))/(4pi in_0r_0) and KE_(p)=((Ze^2)(e))/(4pi in_0r_0)` Clearly, `KE_P=1/2 KE_(alpha)`.

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In Rutherford scattering experiment, if a proton is taken instead of an alpha particle, then for same distance of closest approach, how much K.E. in comparison to K.E. of a particle will be required?

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