1.

In S_(N)2 reaction, the correct order of reactivity for the following compounds: CH_(3)Cl,CH_(3)CH_(2)Cl,(CH_(3))_(2)CHCl and (CH_(3))_(3)C Cl is

Answer»

`(CH_(3))_(2)CHCl GT CH_(3)CH_(2)CL gt CH_(3)CL gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt (CH_(3))_(2) CHCl gt CH_(3)CH_(2)Cl gt (CH_(3))_(3)C Cl`
`CH_(3)Cl gt CH_(3)CH_(2)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`
`CH_(3)CH_(2)Cl gt CH_(3)Cl gt (CH_(3))_(2)CHCl gt (CH_(3))_(3)C Cl`

Solution :As the SIZE of the alkyl group increases in the order: `CH_(3),CH_(3)CH_(2),(CH_(3))_(2)CH,(CH_(3))_(3)C`, steric hindrance increases in the same order and hence the reactivity of the corresponding alkyl halides DECREASES in the same order, i.e., option (c) is correct.


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