In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. ThenA. voltage of the source will be leading current in the circuitB. voltage drop across each element will be less than the applied voltage.C. power factor of circuit will be `4//3`D. none of these.

In series LCR circuit voltage drop across resistance is 8V, across ind

1.	In series LCR circuit voltage drop across resistance is 8V, across inductor is 6V and across capacitor is 12V. ThenA. voltage of the source will be leading current in the circuitB. voltage drop across each element will be less than the applied voltage.C. power factor of circuit will be `4//3`D. none of these.
Answer» Correct Answer - D Since `cos phi =(R )/(Z) =(IR)/(IZ) =8/10=4/5` (also `cos phi` can never be greater than 1) Hence, (c ) is wrong . Also, `IX_(C ) gtIX_(L) implies (X_C) gt(X_L)` `:.` Current will be leading In and LCR circuit, `V=sqrt((v_(L)-v_(C ))^(2)+c_(R )^(2))=sqrt((6-12)^(2)+8^(2))` `V=10,` which is less than voltage drop across capacitor.

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