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In shuffling a pack of cards 3 are accidently dropped, then thechance that missing card should beof different suits is? |
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Answer» 6561 / 62475Step-by-step explanation:Probability of the first card to be from any suit = 1 (can be any card)Probability of the second card to be from any other suit =Favorable cards = 52 (Total no. of cards) - 13 (cards from the first suit) = 39Total remaining cards to choose from = 52 - 1 (one card is already removed)P(E) = 39 / 51Similarly., P(E) of the other 2 cards will be 26 / 50 = 13 / 25 , and 13 / 49.Total probability = 1*39*13*13 / 51*25*49 = 6561 / 62475 HOPE it's help YOUMARK as BRAINLIST |
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