In shutting a pack of 52 playing cards, four are accidently dropped; f

1.	In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit
Answer» Given: A pack of 52 cards from which 4 are dropped. By using the formula, P (E) = favourable outcomes / total possible outcomes We now have to find the probability that the missing cards should be one from each suit We know that, from well shuffled pack of cards, 4 cards missed out total possible outcomes are n (S) = ⁵²C₄= 270725 Let E be the event that four missing cards are from each suite n (E) = ¹³C₁× ¹³C₁× ¹³C₁× ¹³C₁= 13⁴ P (E) = n (E) / n (S) = 13⁴ / 270725 = 2197/20825

In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit

Answer»

Given: A pack of 52 cards from which 4 are dropped.

By using the formula,

P (E) = favourable outcomes / total possible outcomes

We now have to find the probability that the missing cards should be one from each suit

We know that, from well shuffled pack of cards, 4 cards missed out total possible outcomes are

n (S) = ⁵²C₄= 270725

Let E be the event that four missing cards are from each suite

n (E) = ¹³C₁× ¹³C₁× ¹³C₁× ¹³C₁= 13⁴

P (E) = n (E) / n (S)

= 13⁴ / 270725

= 2197/20825

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In shutting a pack of 52 playing cards, four are accidently dropped; find the chance that the missing cards should be one from each suit

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