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In SOCl_(2), the Cl-S-Cl and Cl-S-O bond angles are |
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Answer» `130^(@) and 115^(@)` Hybridization of `S = (1)/(2) [1 XX 6 (S) + 0 (=0) + 2 xx 1 (Cl) ] = 4` Thus, S is `sp^(3)`-hydridized. Since `SOCl_(2)` has only three `sigma`-bonds, therefore, it has one lone pair and hence its shape is pyramidal. Further, since `pi`- electrons of the S = O bond are more polarized, therefore, they repel the bond pair of S-Cl bonds. In other words, Cl-S-O bond angle `(106^(@))` is larger than Cl-S-Cl bond angle `(96^(@))`. Hence, option (d) is correct.
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