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In solution of H_(2)SO_(4)when SO_(3) is bubbled, a compound 'A' is formed, which further reacts with H_(2)O to give H_(2)SO_(4). Explain this process with equation ? |
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Answer» Solution :`H_(2)SO_(4)` absorbs `SO_(3)` forming oleum (A) which reacts with `H_(2)O` to form `H_(2)SO_(4)` `H_(2)SO_(4) + SO_(3) RARR UNDERSET("Oleum, A")(H_(2)S_(2)O_(7))overset(H_(2)O)rarr 2H_(2)SO_(4)` |
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