1.

In space charge limited region, the plate current in a diode is 10 mA for a plate voltage 150 V. If the plate voltage is increased to 600 V, then the plate current will be

Answer»

`10 mA`
`40 mA`
`80 mA`
`160 mA`

Solution :In space CHARGE limited region, the plate current in given by CHILD's law `i_(p)=KV_(p)^(3//2)`
Thus, `(i_(p_(2)))/(i_(p_(1)))=((V_(p_(2)))/(V_(p_(1))))^(3//2)=(600/150)^(3//2)=(4)^(3//2)=8`
or `i_(p_(2))=i_(p_(1))xx8=10xx8mA=80mA`


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