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In telescope, ratio of resolving power due to light of lambda. = 4000Å and lambda = 6000Å is ...... |
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Answer» `4:5` `=(D)/(1.22 lambda)` D and 1.22 are constant. `:.` Resolution power `prop (1)/(lambda)` `:.` Ration `=(lambda_(2))/(lambda_(1))=(6000)/(4000)=(3)/(2)` |
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