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In terms of potential difference V, electric current I, permitivity `epsi_(0)`, permeability `mu_(0)` and speed of light c, the dimensionally correct equations (s) is (are) :A. `mu_(0)I_(2)=epsiV^(2)`B. `mu_(0)I=mu_(0)V`C. `I=epsi_(0)V`D. `mu_(0)cI=epsi_(0)V` |
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Answer» Correct Answer - a, c `[V]=[M^(1)L^(2)T^(-3)A^(-1)]` `[I]=[A]` `[c]=[L^(1)T^(-1)]` `[epsi_(0)]=[M^(-1)L^(-3)T^(4)A^(2)]` `[mu_(0)]=[M^(-1)L^(1)T^(-2)A^(-2)]` Option (a) : `[mu_(0)I^(2)]=[M^(1)L^(1)T^(-2)]` `[E_(0)V^(2)]=[M^(1)L^(1)T^(-1)]` Option (b) : `[epsi_(0)I]=[M^(1)L^(-3)T^(4)A^(3)]` `[mu_(0)V]=[M^(2)L^(3)T^(-5)A^(-3)]` Option (c) : `[I]=[A]` `[epsi_(0)cV]=[A]` Option (d) : `[mu_(0)cI]=[M^(1)L^(2)T^(-3)A^(-1)]` `[epsi_(0)V]=[L^(-1)TA]` Options (a) and (c) correct. |
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