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The circular scale of a screw gauge has 50 divisions and pitch of 0.5 mm. Find the diameter of sphere. Main scale reading is 2. A. 1.2 mmB. 1.25 mmC. 2.20 mmD. 2.25 mm

Answer» Correct Answer - a
Least count `=("Pitch")/("Number of division on circuit scale")=0.5/50`
`=0.01 mm`
Now, diameter of ball `=(2xx0.5)+(2.5-5)(0.01)=1.2 mm`


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