1.

In terms of SI base units , ohm stands for

Answer»

`(kg m^(2)) //(As)`
`(kg m^(2))//(A^(2) s^(2))`
`(kg m^(2))//(A^(2) s^(2))`
`(kg m^(2)) // (A^(2) s^(3))`

SOLUTION :In SI units , `Omega = (kg m^(2))// (A^(2) s^(3))` .
`Omega = (V)/(A) = ("WORK")/("charge") xx (1)/(A) = (F xx l )/(A xx s) xx (1)/(A)`
`= (m xx a xx l)/(A^(2) s) = (kg ms^(-2) xx m)/(A^(2) s) = (kg. m^(2))/(A^(2) .s^(3))`


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