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In the above problem, if the coil rotates with a constant angular velocity omega, the emf indiuced in it |
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Answer» (a) is ZERO if the normal to the plane of the COIL makes an angle `theta` with the DIRECTION of `B`, the flux linked with the coil is `phi = Ban COS theta` `= Ban cos (omegat)` `e.m.f. = e = (-dphi)/(dt) = Banomegasin(omegat)` |
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