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In the above problem, what force should the man exert on the rope to get his correct weight on the machine? |
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Answer» Solution :`T-CANCEL(MG) + cancel(Mg) = Ma` `(THEREFORE R=Mg) , a=T/M` `T-Mg -mg = ma` `T = m.T/M =(m+M)g` `T=((m+M)Mg)/(M-m) = ((30+60)60 XX 10)/(60-30)` `=(cancel(90) xx 600)/(cancel(30)) = 1800 N` 
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