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In the above problem what force should the man exert on the rope to get his correct weight on the machine ? |
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Answer» Solution :`T-CANCEL(Mg)+cancel(Mg)=Ma` `(because R=Mg)a=(T)/(M)` `T-Mg-mg=ma` `T-m(T)/(M)=(m+M)g` `T=((m+M)Mg)/(M-m)=((30+60)60xx10)/(60-30)` `=(""^(3)cancel(90)xx600)/(cancel(30))=1800 N` 
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