1.

In the above question if the inital velocity of projection above the plane is u, the distance up to which the block can rise up is:

Answer»

`(u^(2))/(4g SIN THETA)`
`(u)/(4g sin theta)`
`(u^(2)sin theta)/(4g)`
`(usin theta)/(4g)`

Solution :Here `upsilon^(2)-u^(2) = 2aS` In this CASE
`0-u^(2) =2(-2g sin theta).S or S=(u^(2))/(4g sin theta)`
(a) is the CHOICE.


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