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In the above question, the amount of salt in the tank at the moment of overflow isA. 20 lbB. 50 lbC. 30 lbD. None of these |
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Answer» Correct Answer - D `(dQ)/(dt)+2/(10+2t)Q=4` This is a linear equation, It solution is `Q=(40t+4t^(2)+c)/(10+2t)`……….(1) At `t=0, Q=a=0`. Substituting these values into equation (1), we find that c=0. We require Q at the moment of overflow which from part (a) is t=20. Thus, `Q=(40(20)+4(20)^(2))/(10+2(20))=40 lb` |
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