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In the above question, the capacitive reactance in the circuit isA. `100 Omega`B. `25 Omega`C. `sqrt(125xx75)Omega`D. `400 Omega`

Answer» Correct Answer - C
Impadance `Z=(E_V)/(I_V) or Z = (200)/(2) = 100 Omega`
But ` Z^(2) = R^(2)+((1)/(omega c))^(2)`
or ` ((I)/(omega C))^(2) Z^(2) -R^(2) = (100)^(2) -(25)^(2) = 125 xx 75`
or, `X_(C) =(1)/(omega C) = sqrt(125 xx 75 ) Omega`.


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