In the above question, the displacement of particle at t = 1 sec and x

1.	In the above question, the displacement of particle at t = 1 sec and x = 4 cm is:
Answer» 4 cm 2cm 1cm Zero Solution :We use`y = a sin" (2pi)/(lambda)(vt - x)` `y = 2sin" (2pi)/(lambda) (24t - x)` t = 1, x = 4CM `y = 2sin ((2pi)/(16) xx20)` = `2sin(2pi + (pi)/(2)) = y = 2cm`

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In the above question, the displacement of particle at t = 1 sec and x = 4 cm is:

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