1.

In the above question the instantaneous power developed by the gravitational force at time t will be :

Answer»

`(1)/(2)Mg t^(2)`
`Mg t^(2)`
`2//3Mg^(2)t`
`Mg^(2)t`

SOLUTION :Here POWER = Force `XX` velocity
`P=Mgxxv`
But `v=0+at`
`therefore P=Mgxxat""(because a=2G//3)`
`=Mgxx(2g)/(3)xxt`
`P=2//3Mg^(2)t`


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