1.

In the above question, the reading of ammeter is 200//x mA. What is the value of x?

Answer»


Solution :`(4 - V_(1))/(100) = (V_(1) - 1)/(100) + (V_(1) - 0)/(100)` or `V_(1) = (5)/(3) V`
CURRENT in ammeter (II)`= (V_(1) - 1)/(R ) = ((5//3) - 1)/(200) = (2)/(300) A = (20)/(3) mA`


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