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In the above question, the speed of each ball relative to ground just after they leave the disc is - |
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Answer» `(Romega_(0))/(sqrt3)` Let the speed of each ball just after they leave the disc be V. From conservation of energy `(1)/(2)[(1)/(2)mR^(2)]omega_(0)^(2)=(1)/(2)[(1)/(2)mR^(2)]omega^(2)+(1)/(2)[("m")/(2)]v^(2)+(1)/(2)[("m")/(2)]v^(2)` solving we get `v=(2Romega_(0))/(3)` NOTE : `v=sqrt((OMEGAR)^(2)+V_(r)^(2)) , V_(r)` = RADIAL velocity of tha ball |
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