1.

In the above question the value of stress is :

Answer»

`(Wl)/(2xA)`
`(Wl)/(4xA)`
`(2xW)/(lA)`
`(4xW)/(lA)`

Solution :From the fig. it is clear 2T COS `theta` = W
`T=W/(2costheta)`
Now cos `theta=x/(sqrt(l^(2)+x^(2)))`
`costheta=x/(l[1+(x^(2))/(2l^(2))])`
If `(x^(2))/(2l^(2))` is neglected being small then cos `theta=x/lthereforeT=W/(2X)`
stress`=T/A=(((Wl)/(2x)))/A(Wl)/((2x)/A)=(Wl)/(2Ax)`
CORRECT CHOICE is (a).


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