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In the above question what is the force acting after 2 sec ? |
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Answer» `(4overset(WEDGE)(i)+8overset(wedge)(J))N` `:.veca=(dvecupsilon)/(dt)=2hati+2thatj` Now at 2 `sec veca_(t)=(2hati+4hatj)` `vecF=2(2hati+4hatj)` `=(4hati+8hatj)N` Hence (a) is the right CHOICE. |
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