1.

In the above question what should be the minimum height of plane so that it may not be hit by the shell ? (g = 10 ms^(-2) ):

Answer»

1 km
3km
2km
4km

Solution :In question 95, maximum height reached by SHELL is
`H=(u^(2)sin^(2)theta)/(2G)=((200sqrt(2))^(2)xx(1/sqrt(2))^(2))/(2XX10)`
H=2000m=2km


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